Suman sold two items, each for Rs. 2,500. She made a profit of 25% on the first item and incurred a loss of 16.67% on the second item. Calculate the total cost price of both items.
Cost price of the first item = 2500 X (4/5) = Rs. 2000 Cost price of the second item = 2500 X (6/5) = Rs. 3000 Therefore, required sum = (2000 + 3000) = Rs. 5000
1672 ÷ 19 = ?% of 220
Solve: 3/4÷2/3
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
1200% of 18 + √1600 + 62 = ?2 + (90 of 0.4)
216% of 350 + 273 = ?2 × 21
What is (0.08% of 0.008% of 8)1/9 ?
1200 - 60 X 6 + 30 = 30 X 20 + ?
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
(15 × 16) + 242= ? × 16