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Let the cost price of the article be Rs. '100x'. So, the selling price = 100x X 1.38 = Rs. '138x' Now, marked price of the article = (138x ÷ 0.92) ÷ 0.75 = 150x ÷ 0.75 = Rs. '200x' ATQ, new selling price of the article = 200x X 0.82 = Rs. '164x' So, required profit percentage = {(164x – 100x)/100x} x 100 = 64%
I. 64x2 - 64x + 15 = 0
II. 21y2 - 13y + 2 =0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
l). 2p² - 10p - 48 = 0
ll). q ² + 5q - 234 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 8x – 3y = 85
II. 4x – 5y = 67
I. 4x2+ 25x + 36 =0
II. 2y2+ 5y + 3 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.?
...I. 77x² - 25x – 72 = 0
II. 42y² + 13y – 42 = 0
I. 9/(4 )p + 7/8p = 21/12
II. 7/5p = 9/10q + 1/4
