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Let the cost price of article be Rs. 100a
Selling price of article = 1.2 X 100a = Rs. 120a
So, 120a + 240 = 1.4 X (100a - 400)
Or, 120a + 240 = 140a - 560
Or, 20a = 800
Or, a = 40
Therefore, required selling price = 1.28 X 100a = 128a = 128 X 40 = Rs. 5,120
I. 3p2 - 11p + 10 = 0
II. 42q2 + q -1 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 17x² - 94x + 120 = 0
Equation 2: 13y² - 45y + 13...
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 26x + 168 = 0
Equation 2: y² - 23y + 132 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 2x2 - 9 x + 9 = 0
II. 2y2 - 7 y + 3 = 0
I. p2 +7p + 10 = 0 II. q2- q – 6 = 0
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0