Question
A person bought some mangoes at the rate of 7 per rupee.
He bought the same number of mangoes at the rate of 6 per rupee. He mixes both types and sells at 14 for rupees 6. In the business he earns a profit of Rs. 46. How many mangoes he bought in all.ÂSolution
Suppose he bought x mangoes of each quality. Then his total investment (cost price) = x/7+x/6=13x/42 rupees. The total number of mangoes bought is 2x (since he bought x mangoes at each rate). He sells them at the rate of 14 for 6 rupees. Therefore, the selling price per mango is 6/14=3/7 rupees The selling price for 2x mangoes =2x =2×3/7 =6x/7 rupees. ATQ- Profit =6x/7 -13x/42 6x/7 -13x/42 =46 36x-13x/42 =46 23x/42 =46 X =84. The total number of mangoes bought =2×84 =168.
The sum and difference of L.C.M and H.C.F of two numbers is 216 and 184. If one of the numbers is 25, then find the other number.
The smallest number which when divided by 29 and 33 leaves remainder 11 and 15 respectively is:
Two numbers are in the ratio 5:7. The product of their H.C.F. and L.C.M. is 5040. The sum of the numbers is:
The LCM and the HCF of the numbers 42 and 60 are in the ratio:
HCF of two numbers 70 and 140 can be expressed in the form of (20m – 110) whereas LCM of these two numbers can be expressed in the form of (40n – 20...
The ratio of two number is 6 : 5 and their HCF is 15. So find and their LCM?
Three numbers are in the ratio 2:3:6 respectively. If the HCF of the numbers is 5, then find the LCM of the numbers.
The sum of two numbers is 99 and their HCF is 9. Total number of such pairs of numbers is?  Â
Three numbers are in the ratio 4 : 9 : 13 and their LCM is 2340. Their HCF is: