Answer-I. 2(x+2)+ 2(-x)=5 II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))

2x2 2-x5 2x 2 12x - 50 Put 2x a We get 4a 1a- 50 4a1-5a0 4a-4a-a10 4a-1a-1 0 a1,14 If 2x1 x0 2x14 If, 2x12 x -2 1y1 1y51y2 1y4 1y1- 1y41y2- 1y5 y4-y-1y1y4 y5-y-2y2y5 3y1y4 3y2y5 1y1y4 - 1y2y50 y2y5- y1y4y1y4y2y50 y7y10-y2 5y40 y7y10-y-5y-40 2y60 y -3 Hence, xy

Question

I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))

In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;

A x < y

B x > y

C x = y or no relationship cannot be established between x and y

D x ≥ y

E x ≤ y

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I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))

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I. 2(x+2)+ 2(-x)=5II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))

Detailed Solution

More Quadratic equation Questions

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I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))