Question
I. 7x² + 27x + 18 = 0 II. 19y² - 27y + 8 =
0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;Solution
I. 7x² + 27x + 18 = 0 7x² + 21x + 6 x + 18 = 0 7x(x + 3) + 6 (x + 3) = 0 (7x + 6) (x + 3) = 0 x = -6/7 , - 3 II. 19y² - 27y + 8 = 0 19y² - 19y - 8 y + 8 = 0 19y(y – 1) – 8(y – 1) = 0 (y – 1)(19 y – 8) = 0 y = 1, 8/19 Hence, x < yÂ
If x and y are two digits of the number 85254xy such that this number is divisible by 90. Find the minimum value of x + y?
If we add 1 to the numerator and subtract 1 from the denominator a fraction becomes 1. It becomes 1/4 if we only add 7 to the denominator what is the fr...
Find the unit digit in (257)45 × (248)73.
- How many numbers in the range from 50 to 500 are divisible by 3, 6, and 9?
The digits of a two-digit number ‘N’ are reversed to form a new number ‘M’. If M < N and N – M = 45, then which of the following maybe ‘N’...
- The smallest positive integer 'R' which when divided by 9, 18, and 27 leaves 6 as the remainder in each case. Find the value of ('7R' - 20).
The numerator of a fraction is 7 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 5, then the denominat...
Sum of all positive integers from 1 to 100 is
Find the value of 'a' in the given data if the mean of the given data is 20.
10, 15, 18, 22, 24, 19, 21, a, 16, 25
99² +? ² = 18826
Relevant for Exams:
