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    Question

    I. 35x² + 83x + 36 = 0

    II. 42y² + 53y + 15 = 0

    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x = y or no relationship cannot be established between x and y. Correct Answer Incorrect Answer
    D x ≥ y Correct Answer Incorrect Answer
    E x ≤ y Correct Answer Incorrect Answer

    Solution

    I. 35x² + 83x + 36 = 0 35x² + 63x + 20x + 36 = 0 7x (5x + 9) + 4(5x + 9) = 0 (7x + 4) (5x + 9) = 0 x = - 4/7 , - 9/5 II. 42y² + 53y + 15 = 0 42y² + 18y + 35y + 15 = 0 6y(7y + 3) + 5(7y + 3) (6y + 5) (7y + 3) = 0 y = - 5/6 , - 3/7 Hence no relationship can be established.

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