Question
I. 8x² + 2x – 3 = 0 II. 6y² + 11y + 4 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 8x² + 2x – 3 = 0 8x² + 6x - 4x – 3 = 0 2 x (4 x + 3) – 1(4 x + 3) = 0 (2x – 1) (4x + 3) = 0 x = 1/2, -3/4 II. 6y² + 11y + 4 = 0 6y² + 8y + 3y + 4 = 0 2 y(3 y + 4) + 1(3 y + 4) = 0 (2 y + 1) (3 y + 4) = 0 y = - 1/2, -4/3 Hence, no relationship can be established between x and y
If tan 4θ = cot 14θ, then find the value of cos 9θ.
If sin(3θ) = cos(2θ), then find the value of θ between 0 and 90 degrees.
- Calculate the value of sin120 o + cos180 o + tan225 o .
Find the value of `1/2` cosec 10 - `2/(cosec 70)` ?
- Find the value of sin30° + cos 60° + tan45° + cosec²45° + sec²45°.
If 4sin² θ = 3(1+ cos θ), 0° < θ < 90°, then what is the value of (2tan θ + 4sinθ - secθ)?
The minimum value of 45 sin2 θ + 28 cos2 θ is
What is the value of cos [(180 – θ)/2] cos [(180 – 9θ)/2] + sin [(180 – 3θ)/2] sin [(180 – 13θ)/2]?
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...
