Question
I. 20y² - 13y + 2 = 0 II. 6x² - 25x +
14 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 20y² - 13y + 2 = 0 20y² - 8y - 5y + 2 = 0 4y (5y – 2) – 1(5y – 2) = 0 (4y – 1) (5y – 2) = 0 y =2/5, 1/4 II. 6x² - 25x + 14 = 0 6x² - 21x - 4x + 14 = 0 3x (2x – 7) - 2 (2x – 7) = 0 (3x – 2) (2x – 7) = 0 x = 7/2 , 2/3 Hence, x>y
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 90...
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
l). 2p² - 10p - 48 = 0
ll). q ² + 5q - 234 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0Â
I. 3x² - 22 x + 40 = 0 Â
II. 4y² + 22y + 24 = 0  Â
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
I.√(3x-17)+ x=15
II. Â y+ Â 135/y=24Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 92x + 73 = 0
Equation 2: 17y² - 76y + 59 = 0
I. 77x² - 25x – 72 = 0
II. 42y² + 13y – 42 = 0
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