I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
I. 8x² - 78x + 169 = 0 => (4x - 13) (2x – 13) = 0 ⇒ x = 13/4 , 13/2 II. 20y² - 117y + 169 = 0 => (4y -13) (5y – 13) = 0 ⇒ y = 13/4 , 13/5 Hence, x ≥ y
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