I. x³= ((4)5+ (15)³)/(3)4
II. 8y³=(-13)3÷ √1521+ (3y)³
I. x³= ((4)5 + (15)³)/(3)4 x³= (1024+3375)/81 = 4399/81 = 54 x³=54 x= ∛54 II. 8y³= (-13)3 ÷ √1521+ (3y)³ 8y³= -2197 ÷39 + 27y³ y³= 56/19 y= ∛(56/19) Hence, x > y
The value of 0∫π cos3x dx is –
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