Question
I. (x13/5 ÷7) = 5488 ÷
x7/5 II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3Solution
I. (x(13/5) ÷7) = 5488 ÷ x(7/5) x(13/5 + 7/5) = 5488 ×7 x4 = 38416 x = ± 14 II. {(y)(2/3) × y(2/3)} ÷ √4 = (343y)(1/3) y(4/3) ÷ y(1/3) = 2 × 7 y=14 Hence, y ≥ x
What is the standard range of a CIBIL score used for individual credit evaluation in India?
Price risk is the risk of a decline in the value of a security or a portfolio. How can one transfer price risk?
The type of e-Commerce where consumer posts work online and businesses make offers is:Â
Which act primarily governs the field of general insurance in India?
An unfavourable material usage arises because of:
Which accounting treatment is appropriate for assets given on finance lease (lessee perspective) under Ind AS?
A retailer begins the month with 200 units valued at ₹50 per unit. During the month, they purchase 300 units at ₹55 and later 500 units at ₹60. By...
Depreciation starts on a machine from the date:
Provision of section 139(3) of the income Tax Act, 1961 is relating to ______.
As per Union Budget 2025-26, the Mission for Aatmanirbharta in Pulses will focus on which three pulse crops?
Relevant for Exams:
