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I. (4x-5)3+ 1/(4x-5)3 = 2 Let 4x-5=a a3+ 1/a3 =2 a6+ 1=2a³ a6-2a³+ 1=0 (a3- 1)2= 0 a³=1 a=1 4x-5=1 x= 3/2 II. 2[(y+1/y)2- 2]- 9(y+1/y)= -14 Put (y+1/y)=b 2[b2-2]-9b+14=0 2b2- 4-9b+14=0 2b2-9b+10=0 2b2-5b-4b+10=0 b(2b-5)-2(2b-5)= 0 b=2,5/2 If (y+1/y)= 2 y²+1=2y y²+1-2y=0 (y-1)2= 0 y=1 If, (y+1/y)= 5/2 2y2+2=5y 2y2+2-5y=0 2y2- 4y-y+2=0 2y(y-2)-1(y-2)=0 y=2,1/2 Hence, relationship between x and y cannot be established
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