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I. 27x6-152x3+125=0 Let x³ = a 27a2-152a+125=0 27a2-125a-27a+125=0 a(27a-125)-1(27a-125)=0 a=1,125/27 x³=1,125/27 x=1,5/3 II. 216y6- 91y3 + 8=0 Let y3=b 216b2-91b+8=0 216b2-27b-64b+8=0 27b(8b-1)-8(8b-1)= 0 b=1/8,8/27 y3= 1/8,8/27 y=1/2,2/3 Hence, x>y
The perimeter of a rectangular field is 240 meters, and its length is 20% more than its breadth. What is the area of the field?
If O is circumcentre of acute angled triangle ABC, if ∠ OBC = 300 then ∠BAC = ?
In ΔABC, PQ is parallel to BC If AP: PB= 3:5 and AQ= 3 cm, AC is equal to?
The perimeter of a rectangle is 100 m, and its diagonal is 41 m. Find the area of the rectangle.
In a rectangle PQRS, there is a point A located within the interior of the rectangle. The distances from point A to three vertices of the rectangle are ...
Let G be the centroid of the equilateral triangle ABC of perimeter 24 cm. Then the length of AG is
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In the given figure. ‘O' is the centre of the circle and ∠BCA = 50°. The value of ∠BDA is:
Find the area of triangle having sides 8 m, 9 m, and 13 m.