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    Question

    I. 3x2 + 3x - 60 = 0         

    II. 2y2 - 7y + 5 = 0 
    A if x > y Correct Answer Incorrect Answer
    B if x < y Correct Answer Incorrect Answer
    C if x ≥ y Correct Answer Incorrect Answer
    D if x = y or the relationship cannot be established. Correct Answer Incorrect Answer
    E if x ≤ y Correct Answer Incorrect Answer

    Solution

    I. 3x2 + 3x - 60 = 0   Pairs = 15, -12 And now dividing by a and by changing the sign we get,  x = -5, 4 II. 2y2 - 7y + 5 = 0  Pairs = -2, -5 And now dividing by a and by changing the sign we get,  y = 1, 2.5 From these comparisons, we can see that x1(4) is greater than both y₁ (2.5) and y2 (1), while x2(-5) is less than both y1 (2.5) and y2(1). Since one root of x is greater than both roots of y and the other root of x is less than both roots of y, we cannot establish a consistent relationship between x and y. ∴ The relationship between x and y cannot be established.

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