I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
I. x2-2x- √5x+2√5 = 0 x(x-2)- √5 (x-2) = 0 (x-2)( x-√5) = 0 x = 2,√5 II. y2-√3 y- √2 y+ √6 = 0 y (y- √3)-√2 (y-√3) = 0 (y- √3)( y- √2 )= 0 y=√3,√2 Hence, x>y
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