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    Question

    I. y/16 = 4/y┬а II. x3┬а= (2 ├╖ 50) ├Ч

    (2500 ├╖ 50) ├Ч 42┬а├Ч (192 ├╖ 12)
    A If x > y Correct Answer Incorrect Answer
    B If x тЙе y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x тЙд y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. y/16 = 4/y y 2 = 16 ├Ч 4┬а y 2 = 64 y = ┬▒ 8 II. x3 = (2 ├╖ 50) ├Ч (2500 ├╖ 50) ├Ч 42 ├Ч (192 ├╖ 12) x3 = 2/50 ├Ч 2500/50 ├Ч 42 ├Ч 192/12┬а x3 = 512 x = 8 Hence, x тЙе y

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