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    Question

    I. 8x² + 2x – 3 = 0 II. 6y² + 11y + 4 =

    0
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x< y Correct Answer Incorrect Answer
    D if x = y or the relationship cannot be established Correct Answer Incorrect Answer
    E if x ≤ y Correct Answer Incorrect Answer

    Solution

    I. 8x² + 2x – 3 = 0 Pairs are 6,-4 So by changing its signs & dividing by a i.e.8, we will get x = -6/8, 4/8  = -3/4,1/2 II. 6y² + 11y + 4 = 0 Pairs are 3,8 So by changing its signs & dividing by a i.e.6, we will get y = -3/6, -8/6 = - 1/2, -4/3 Hence, no relationship can be established between x and y.

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