Question
I. 49y2 + 35y + 6 = 0 II.
12x2 + 17 x + 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 49y2 + 35y + 6 = 0 49y2 + 21y + 14 y + 6 = 0 7 y (7 y + 3) + 2 (7 y + 3) = 0 (7 y + 2) (7 y + 3) = 0 y = -2/7, -3/7 II. 12x2 + 17 x + 6 = 0 12x2 + 8 x + 9 x + 6 = 0 4 x (3 x + 2) + 3 (3 x + 2) = 0 (4 x + 3) (3 x + 2) = 0 x = -3/4, -2/3 Hence, x < y
20% of 1500 – 75% of 200 = 125% of ?Â
24% of 150% of 500 + 140 = ? × 8Â
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?

40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)