New SIDBI Grade A New Batch Starts on Nov 18

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    Question

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer.

    I. 3 x² - 10 + 3 = 0

    II. 2x ² - 5 + 3 = 0

    A If x ≥ y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x > y Correct Answer Incorrect Answer
    D If x < y Correct Answer Incorrect Answer
    E If x = y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 3 [if gte msEquation 12]> x [if !msEquation]--> x² - 10 [if gte msEquation 12]> x [if !msEquation]--> x+ 3 = 0 (3 [if gte msEquation 12]> x [if !msEquation]--> x– 1) ( [if gte msEquation 12]>x [if !msEquation]--> x– 3) = 0 [if gte msEquation 12]>⇒ x [if !msEquation]--> [endif]-->x = 3,`(1)/(3)` [if gte msEquation 12]> 1 3 [if !msEquation]--> [endif]--> II. 2 y² - 5 y+ 3 = 0 (2 [if gte msEquation 12]> y [if !msEquation]--> y– 3) ( [if gte msEquation 12]>y [if !msEquation]--> [endif]-->y– 1) = 0 y = 1,`(3)/(2)` [if gte msEquation 12]> 3 2 [if !msEquation]--> [endif]--> Hence, relationship cannot be established.

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