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    Question

    The equation q2 - 17x + C = 0, has two roots ‘x’ and ‘y’ such that (x – y) = 7. Find an equation which is equal to thrice of the given equation.

    A 3q^2 + 51q + 180 Correct Answer Incorrect Answer
    B 3q^2 + 48q + 180 Correct Answer Incorrect Answer
    C 3q^2 + 54q + 180 Correct Answer Incorrect Answer
    D 3q^2 + 60q + 180 Correct Answer Incorrect Answer
    E 3q^2 + 63q + 180 Correct Answer Incorrect Answer

    Solution

    Given, q2 - 17x + C = 0 Since, sum of roots of the equation = 17 Therefore, x + y = 17……. (1) And, x – y = 7……. (2) On solving equation (1) and (2), we get x = 12 and y = 5 Desired equation = (q - 12)(q - 5) = 0 => q2 + 17q + 60 = 0 So, 3 × (q2 + 17q + 60) = 0 => 3q2 + 51q + 180 = 0

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