Question
I. x2 + x – 42 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
More Quadratic equation Questions
- Solve the quadratic equation: 5x² − 13x + 6 = 0
- I. 2p² - 11p + 12 = 0 II. 2q² - 17q + 36 = 0
- I. 2x² + 15 x - 27 = 0 II. 3 y² + 25 y - 18 = 0
- (i) 2x² – x – 3 = 0 (ii) 2y² – 6y + 4 = 0
- I. 66x² - 49x + 9 = 0 II. 46y² - 37y - 30 = 0
- In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.I. x2 - 13x + 40 = 0II. y2 - 16...
- For 3x² − 10x − 8 = 0, find (1/α + 1/β).
- I. (x13/5 ÷7) = 5488 ÷ x7/5 II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3
- I. 6x² + 37x + 45 = 0 II. 3y² - 11y + 6 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: x² - 5x + 6 = 0 Equation 2: y² - 7y + 12 = 0
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