ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    I. x2 + x тАУ 42 = 0 II. y2

    + 6y тАУ 27 = 0 In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
    A if x > y Correct Answer Incorrect Answer
    B if x тЙе y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x = y or relationship cannot be established. Correct Answer Incorrect Answer
    E if x > y Correct Answer Incorrect Answer

    Solution

    I. x2┬а+ x тАУ 42 = 0 => x2┬а+ 7x тАУ 6x тАУ 42 = 0 => x(x + 7) тАУ 6(x + 7) = 0 => (x + 7) (x -6) = 0 => x = -7, 6 II. y2┬а+ 6y тАУ 27 = 0 => y2┬а+ 9y тАУ 3y тАУ 27 = 0 => y(y + 9) тАУ 3(y + 9) = 0 => (y + 9) (y тАУ 3) = 0 => y = -9, 3 Hence, the relationship cannot be established between x and y.

    Practice Next
    More Quadratic equation Questions

    Relevant for Exams:

    ask-question