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    Question

    In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.

    I. 4x2 + 9x - 9 = 0

    II. 4y2 - 19y + 12 = 0

    A if x > y Correct Answer Incorrect Answer
    B if x < y Correct Answer Incorrect Answer
    C if x ≥ y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer

    Solution

    I. 4x2 + 9x - 9 = 0 => 4x2 + 12x – 3x – 9 = 0 => 4x(x + 3) – 3(x + 3) = 0 => (x + 3) (4x -3) = 0 => x = -3, 3/4 II. 4y2 - 19y + 12 = 0 => 4y2 - 16y – 3y + 12 = 0 => 4y(y - 4) – 3(y - 4) = 0 => (y - 4) (4y – 3) = 0 => y = 4, 3/4 Hence, x ≤ y.

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