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    Question

    I. 2x2 + 12x + 18 = 0 II.

    3y2 + 13y + 12 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x Correct Answer Incorrect Answer
    B if x>y Correct Answer Incorrect Answer
    C if x≥y Correct Answer Incorrect Answer
    D if x≤y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. 2x2 + 12x + 18 = 0 => 2x2 + 6x + 6x + 18 = 0 => 2x(x + 3) + 6(x + 3) = 0 => (x + 3) (2x + 6) = 0 => x = -3, -3 II. 3y2 + 13y + 12 = 0 => 3y2 + 9y + 4y + 12 = 0 => 3y(y + 3) + 4(y + 3) = 0 => (y + 3) (y + 4) = 0 => y = -3, -4 Hence, x ≥ y.

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