Question

    I. x2 - 4x – 21 = 0 II.

    y2 + 12y + 20 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
    A If x > y Correct Answer Incorrect Answer
    B If x ≥ y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. x2 - 4x – 21 = 0 => x2 - 7x + 3x – 21 = 0 => x(x – 7) + 3(x – 7) = 0 => (x – 7) (x + 3) = 0 => x = 7, -3 II. y2 + 12y + 20 = 0 => y2 + 10y + 2y + 20 = 0 => y(y + 10) + 2(y + 10) = 0 => (y + 10) (y + 2) = 0 => y = -10, -2 Hence, x = y or the relationship cannot be established.

    Practice Next
    More Quadratic equation Questions

    Relevant for Exams:

    ask-question