I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
I. x2 - 17x + 70 = 0 => x2 - 7x – 10x + 70 = 0 => x(x – 7) – 10(x – 7) = 0 => (x – 7) (x – 10) = 0 => x = 7, 10 II. y2 - 11y + 28 = 0 => y2 - 7y – 4y + 28 = 0 => y(y – 7) – 4(y – 7) = 0 => (y – 7) (y – 4) => y = 7, 4 Hence, x ≥ y.
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