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      Question

      I. 6x2 тАУ 7x - 20 = 0 II.

      3y2┬а- y - 14 = 0 In each of these questions, two equation I and II are given. You have to solve both the equations and give answer:
      A if x > y Correct Answer Incorrect Answer
      B if x < y Correct Answer Incorrect Answer
      C if x тЙе y Correct Answer Incorrect Answer
      D if x тЙд y Correct Answer Incorrect Answer
      E if x = y or no relation can be established between x and y. Correct Answer Incorrect Answer

      Solution

      I. 6x2┬атАУ 7x - 20 = 0 6x2┬атАУ 15x + 8x - 20 = 0 3x(2x - 5) + 4(2x - 5) = 0 (2x - 5) (3x + 4) = 0 x = 5/2, -4/3 II. 3y2┬а- y - 14 = 0 3y2┬атАУ 7y + 6y - 14 = 0 y(3y тАУ 7) + 2(3y тАУ 7) = 0 (y + 2) (3y тАУ 7) = 0 y = -2, 7/3 Hence, the relationship cannot be established between x and y.

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