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ATQ, From I. 4- (22/p)+(18/p)2 = 0  4p2-22p+18=0  4p2-4p-18p+18=0  4p(p-1)-18(p-1)=0  (4p-18) (p-1)=0  p=1,9/2 From II. (q-4)2=16/9  q-4 = ± 4/3  q=16/3, 8/3 New eq. = r^2-ar+b=0 a = sum of root, b= product of root So, highest root of equation I and lowest root of equation II is (9/2) and (8/3) respectively. Required equation = r2- (43/6)r + 12 = 0  6r2- 43r + 72 = 0Â
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