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ATQ, From I: 27(p + 2) = 2p(24 – p) Or, 27p + 54 – 48p + 2p2 = 0 Or, 2p2 – 21p + 54 = 0 Or, 2p2 – 12p – 9p + 54 = 0 Or, 2p(p – 6) – 9(p – 6) = 0 Or, (2p – 9)(p – 6) = 0 Or, p = (9/2) or 6 From II: 2q2 – 25q + 78 = 0 Or, 2q2 – 12q – 13q + 78 = 0 Or, 2q(q – 6) – 13(q – 6) = 0 Or, (2q – 13)(q – 6) = 0 Or, q = (13/2) or 6 Therefore, q ≥ p
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
Equation 1: 2x2 - 21x + 54 = 0
Equation 2: 4y2 - 23y + 15 = 0
Difference between the roots of equation 1 is approx...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 30x + 221 = 0
Equation 2: y² - 28y + 189 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
Solve the given two equations and answer the two questions that follow as per the instructions given below.
I. (1/4) + 7.5p(-2) = 3.62...
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 375 = 0
Equation 2: y² - 36y + 324 = 0