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    Question

    Solve the quadratic equations and determine the relation

    between x and y: Equation 1: x² - 36x + 288 = 0 Equation 2: y² - 36y + 320 = 0
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From Equation 1: x² - 36x + 288 = 0 Factorizing: (x - 12)(x - 24) = 0 So, x = 12 or x = 24. From Equation 2: y² - 36y + 320 = 0 Factorizing: (y - 16)(y - 20) = 0 So, y = 16 or y = 20. Comparing x and y: x = 12, y = 16, x < y x = 12, y = 20, x < y x = 24, y = 16, x > y x = 24, y = 20, x > y Correct option: E) x = y or no relation

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