Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: x² - 42x + 392 = 0 Equation 2: y² - 46y + 480 = 0Solution
From Equation 1: x² - 42x + 392 = 0 Factorizing: (x - 14)(x - 28) = 0 So, x = 14 or x = 28. From Equation 2: y² - 46y + 480 = 0 Factorizing: (y - 16)(y - 30) = 0 So, y = 16 or y = 30. Comparing x and y: x = 14, y = 16, x < y x = 14, y = 30, x < y x = 28, y = 16, x > y x = 28, y = 30, x < y
Simplify the following expression.
{(p² - 2p – 63)/(p² + 14p + 49)}
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