Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: x² - 41x + 400 = 0 Equation 2: y² - 41y + 420 = 0Solution
From Equation 1: x² - 41x + 400 = 0 Factorizing: (x - 16)(x - 25) = 0 So, x = 16 or x = 25. From Equation 2: y² - 41y + 420 = 0 Factorizing: (y - 20)(y - 21) = 0 So, y = 20 or y = 21. Comparing x and y: x = 16, y = 20, x < y       x = 16, y = 21, x < y x = 25, y = 20, x > y x = 25, y = 21, x > y
1299.999 ÷ 325.018 × 24.996 = ?
³√? `xx` 32.87 + 59.83 `xx` 28.7665 – 48.8745 `xx` 21.642 = 1085.344
√2024.84 + (24.86% of 1999.81) - (3/8 of 800.15) = ?
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99Â
(8000)1/3  × 10.11 × 8.97 ÷ 18.32 = ? + 25.022
80.03% of 120.03 + 119.87 × 8.09 ÷ 5.998 = 2.01 ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
59.68% of √400 × 123.95 = ?
√483.98 + 120.02 of 119.89 ÷ 59.87 of 29.87 = ?
244.98% of 189.98% of 599.99 + 199.98 = ?
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