Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: x² - 41x + 400 = 0 Equation 2: y² - 41y + 420 = 0Solution
From Equation 1: x² - 41x + 400 = 0 Factorizing: (x - 16)(x - 25) = 0 So, x = 16 or x = 25. From Equation 2: y² - 41y + 420 = 0 Factorizing: (y - 20)(y - 21) = 0 So, y = 20 or y = 21. Comparing x and y: x = 16, y = 20, x < y       x = 16, y = 21, x < y x = 25, y = 20, x > y x = 25, y = 21, x > y
More Quadratic equation Questions
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? ÷ √ 16
? = 20% of 1200 + 256
21% of 400 − 150 = ? − 77
172Â - 92Â + 121 - 74 = ?
24% of 150% of 500 + 140 = ? × 8Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 × 250) − 200
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