New Enroll for RBI, PFRDA & NABARD Intro Class! April 18 at 9:15 PM

    Question

    Solve the quadratic equations and determine the relation

    between x and y: Equation 1: x² - 45x + 450 = 0 Equation 2: y² - 48y + 540 = 0      
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From Equation 1: x² - 45x + 450 = 0 Factorizing: (x - 15)(x - 30) = 0 So, x = 15 or x = 30. From Equation 2: y² - 48y + 540 = 0 Factorizing: (y - 18)(y - 30) = 0 So, y = 18 or y = 30. Comparing x and y: x = 15, y = 18, x < y x = 15, y = 30, x < y x = 30, y = 18, x > y      x = 30, y = 30, x = y

    Practice Next

    Relevant for Exams: