ATQ, p2 - 20p + 51 = 0 or p2 - 17p - 3p – 51 = 0 or, (p - 17) × (p - 3) = 0 or, p = 17, 3 2q2 - 7q + 6 = 0 Or 2q2 - 4q - 3q + 6 = 0 Or (q - 2) × (2q - 3) = 0 Or, q = 2, 3/2 So, p > q
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