ATQ, I). p2 - 26p +165 = 0 p² - 15p – 11p + 165 = 0 (p - 15)(p - 11) = 0 p = 15, 11 II). q2 + 8q – 153 = 0 q² - 9q + 17q – 153 = 0 (q+17) (q – 9) = 0 q = -17, 9 Therefore p > q.
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