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    Question

    I. x2 – 39x + 360 = 0 II.

    y2 – 36y + 315 = 0
    A x > y Correct Answer Incorrect Answer
    B x < y Correct Answer Incorrect Answer
    C x = y or the relationship cannot be established Correct Answer Incorrect Answer
    D x ≥ y Correct Answer Incorrect Answer
    E x ≤ y Correct Answer Incorrect Answer

    Solution

    From I: x2 – 39x + 360 = 0 Or, x2 – 15x – 24x + 360 = 0 Or, x × (x – 15) – 24 × (x – 15) = 0 Or, (x – 15) × (x – 24) = 0 So, x = 15 or, x = 24 From II: y2 – 36y + 315 = 0 Or, y2 – 15y – 21y + 315 = 0 Or, y × (y – 15) – 21 × (y – 15) = 0 Or, (y – 15) × (y – 21) = 0 So, y = 15 or y = 21 So, the relationship cannot be established. Hence, option c.

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