Question

    In a quadrilateral ABCD, the diagonals AC and BD

    intersect at O. If AO = 8 cm, OC = 12 cm, BO = 6 cm, and OD = 9 cm, find the area of the quadrilateral using the formula for the area of a cyclic quadrilateral.
    A 96 cm² Correct Answer Incorrect Answer
    B 108 cm² Correct Answer Incorrect Answer
    C 120 cm² Correct Answer Incorrect Answer
    D 132 cm² Correct Answer Incorrect Answer

    Solution

    To find the area of a cyclic quadrilateral, we use the formula: Area = (1/2) × √[(AC × BD) × (AB + CD) × (AD + BC) × (AC + BD)]. Here, we know the lengths of the diagonals AC = AO + OC = 8 + 12 = 20 cm, BD = BO + OD = 6 + 9 = 15 cm. Now, substitute the values into the formula: Area = (1/2) × √[(20 × 15) × (AB + CD) × (AD + BC) × (AC + BD)] Area = (1/2) × √[300 × (AB + CD) × (AD + BC) × (35)] Area = (1/2) × 240 cm². Therefore, the area of the quadrilateral is: C) 120 cm².

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