In order that the lines y = x + 1, 2x - 3y + 5 = 0 and 3x - y + m = 0 may meet in a point, the value of m should be:
In solving the equation y = x + 1 and 2x - 3y + 5 = 0, we get x = 2 and y = 3. Since, these three lines are concurrent, therefore, x = 2 and y = 3 will satisfy the equation 3x - y + m = 0 So, 6 - 3 + m = 0 => m = -3
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