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Let HCF = H, LCM = 12H Sum → H + 12 H = 403 or 13 H = 403 H = 31 HCF = 31 So, LCM = 12 × 31 Let no’s 31x & 31y As we know that product of two numbers = product of HCF & product of LCM 31x × 31 y = 31× 12 ×31 ⇒ xy = 12 We cannot take value of x & y = 2 & 6 because these have 2 in common extra but there must be nothing common As 12 HCF is already taken. If values of x, y is (1, 12) ⇒ 1 × 31 = 31, 31 × 12 = 372 → not less than LCM If values of x, yis (3, 4) ⇒ 3 × 31 , 4 × 31 = 93, 124.
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
{(123 + ? × 28) – 1254} × (2328 ÷ 97 – 13) = 8195
Solve for ?.
?² = 37% of 800 – 14 × 18+ 5! - 20
6612 ÷ 19 - ?% of 240 = -2196
(1/8) × (256 × 2)/(8 × 4) + ?3 = 1730
Simplify the following expression:
84 - [21 - {14 - (25 - 16 + 8) }] ÷ 3 X 6
4? + 82 = 22% of 300
779 + 136 – 334 = 270 + 121 + ?