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Let the ages of the second and third children be x years. Their combined age = 2x = 24, so x = 12 years. Let the age of the youngest child be y years, and the eldest be y + 10 years. Average age = (y + (y + 10) + 12 + 12) / 4 = 12 (y + y + 10 + 24) / 4 = 12 (2y + 34) / 4 = 12 2y + 34 = 48 2y = 14 y = 7 years Age of the eldest child = 7 + 10 = 17 years.
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