Let the cost price of the first cow be x. Then the cost price of the second cow will be (4000 – x) Selling price of the first cow = 120% of x Selling price of the second cow = 80% of (4000 - x) Given that both selling prices are the same: 120% of x = 80% of (4000 - x) 3x = 2(4000-x) 3x = 8000-2x 5x = 8000 x = 1600 4000-x = 4000-1600 = 2400
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