In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:
x ² – 10x + 21 = 0
y ² – 8y + 15 = 0
x ² – 10x + 21 = 0 x ² – 7x – 3x + 21 = 0 (x-7) × (x-3) X = 7,3 y² – 8y + 15 = 0 y² –5y – 3y + 15 = 0 (y-5) × (y-3) = 0 Y = 5, 3 Comparing the values of x and y we conclude that the value of y lies between the value of x. S0, relation can’t be determined
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