Question
In a company, there are three departments: A, B, and C.
The average salary of employees in department A is ₹40,000, in department B is ₹50,000, and in department C is ₹60,000. The number of employees in department A is twice that of department B, and the number of employees in department B is three times that of department C. Find the overall average salary of all the employees in the company.Solution
Let the employees in department C = x employees in department B = 3x employees in department A = 6x total salary of department A = 40,000×6x = 240,000x total salary of department B = 50,000×3x = 150,000x total salary of department C = 60,000×x = 60,000x total salary of the company = 240,000x + 150,000x + 60,000x = 450,000x Requires average = 450,000x/10x = 45,000
Out of the four given equations, the first three are solved based on a certain system. Find the correct answer for the unsolved fourth equation on the ...
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(8, 5, 43)
(6, 3, 21)
...Select the related number from the given alternatives:
13 : ? :: 12 : 1729
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VCN, YAQ, BYT, EWW, HUZ, ?
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P __ I __ __ L...
Select the related word/ letters/ number from the given alternatives.
PJQR : QKIJ :: RJDY : ?
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R T _ Y _ _ T V Y Z _ ...
Medicine : Dispensary :: Aeroplane : ?
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S... Select the related number from the given alternatives.
82: 160 :: 36: ?
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