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    Question

    A chemist has three solutions of acid and water. The

    first solution has 40 percent acid, the second has 60 percent acid, and the third has 80 percent acid. He mixes 2 liters of the first solution, 3 liters of the second solution, and 5 liters of the third solution. What is the percentage of acid in the final mixture?
    A 20% Correct Answer Incorrect Answer
    B 66% Correct Answer Incorrect Answer
    C 69% Correct Answer Incorrect Answer
    D 78% Correct Answer Incorrect Answer

    Solution

    ATQ, Amount of acid in the first solution is 0.40 × 2 = 0.8 liters. Amount of acid in the second solution is 0.60 × 3 = 1.8 liters. Amount of acid in the third solution is 0.80 × 5 = 4 liters. Total amount of acid = 0.8 + 1.8 + 4 = 6.6 liters. Total volume of the mixture = 10 liters. Percentage of acid in the mixture = 6.6 / 10 × 100 = 66%

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