To determine when they will meet again at the starting point, we need to find the least common multiple (LCM) of their lap times. LCM of 24 and 30 = 120 Therefore, they will meet again at the starting point after 120 minutes. Answer: A) 120 minutes
Statement: C ≤ D < E; C > F > G
Conclusions: I. F < E II. C > G
...Statements: R < Y ≤ G = S ≥ T; L ≥ O = S < W ≤ U
Conclusions:
I. R < W
II. T ≤ L
Statements: P < Q = R ≥ S = T; R < U; R = W
Conclusion: I. W ≥ T II. U < P
...Statements: D > E ≥ F ≥ G; H < I = G > J
Conclusions: I. J > E II. G < D
...Statements: P % Q, Q & R, R @ S, S # T
Conclusions: I. T & R II. P # S
...Statements: B & A, A # O, O $ Z, Z @ S
Conclusions:
I. Z $ A
II. Z & A
Statements: P ≥ Q ≥ R = S, Q ≥ T > U ≥ V
Conclusion:
I. P ≥ V
II. P > V
Statements: A @ D % J # K & L $ U # O; V $ J # K
Conclusions : I. O @ J II. U # V ...
Statements: R % U, U # V, V @ C, C * F
Conclusions :
I. F $ V
II. C % U
III. R % F
IV. U...
Statement: C ≥ D > E ≥ H; I < E ≤ F < G
Conclusions: I. H > D II. G < H
...