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Let the number of total students in class 10 = 3x Students in section A = x Students in section B = 2x According to question- 2x-15 = 3x/2 0.5x = 15 X = 30 Initially number of students in section A = x = 30 Initially number of students in section B = 2x = 60 After shifting of 15 students, remaining students in section A = 30-15 = 15 Required percentage = 15/90 × 100 = 50/3 %
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Simplify the following trigonometric expression:
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