Let the total work be the LCM of [18, 30] = 90 units. So, the efficiency of 'X' = (90/18) = 5 units/day. Efficiency of 'Y' = (90/30) = 3 units/day. Work done on the first day by 'X' = 5 units. Work done on the second day by 'Y' = 3 units. So, the work done in two days = 5 + 3 = 8 units. Amount of work done in 22 days = 8 × 11 = 88 units. The remaining 2 units will be completed by 'X' on the 23rd day.
0.3Ì…2Ì… + 0.54Ì…8Ì… - 0.1Ì…9Ì… is equal to :
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