50 men takes 10 less days to do a work than 30 men takes time for same work. Find in how many days 15 men can complete the 2/5th of the work?
ATQ, Let 30 men takes time = x days Then, 50 men will take (x-10) days In both the conditions work done will be same 30x = 50(x-10) X = 25 Total work has to be done = 30x = 30 × 25 = 750 unit Work has to be done by 15 men = 2/5 × 750 = 300 unit Time taken by 15 men = 300/15 = 20 days
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