Question
In an election with two candidates, A and B, 80% of
registered voters cast ballots. B wins by a margin of 880 votes. If B had received 10% fewer votes, A's vote count would have matched B's. How many registered voters are there?Solution
Let number of votes received by A = a And, the number of votes received by B = b b-a = 800 according to question- b β 10% of b = a + 10% of b 9b/10 = a + b/10 4b/5 = a a/b = 4/5 from b-a = 880 5x-4x = 880 x = 880 number of votes received by A = a = 4x = 3520 And, the number of votes received by B = b = 5x = 4400 Total casted votes = 3520+4400 = 7920 80% of registered voters = 7920 Registered voters = 7920/80 Γ100 = 9900
What will be the value of expression if the signs β(+)β and β(Γ)β are interchanged?
63 + 7 Γ· 21 Γ 14 β 24 Γ· 6
...If all the alphabets of alphabetical series are numbered as 26-1 from A-Z then what is the sum of the numbers of letters of the word β PARENT β?Β
Which two signs should be interchanged in the following equation to make it correct:
640 Γ· 80 + 6 Γ 20 β 10 = 58