Find the sum of areas of surfaces of an open chalk box that is in the shape of Cuboid.
Statement I: Sum of all three dimensions of the chalk box is 36 cm
Statement II: Square of the length of body diagonal is 464 cm2
Statement I. L + B + H = 36 ………….. (1) Statement II. (L2 + B2 + H2) = 464………… (2) On combining both statement (L + B + H) = 362 L2 + B2 + H2 + 2 x (LB + BH + HL) = 1296 2 x (LB + BH + HL) = 1296 – 464 = 832 We need to calculate the value = LB + 2(BH + HL) This combination is not sufficient to answer the question
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